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Configuration = 12
cycles = (10 8 4 9 5)(7 3 1 6 2)

a = 1, b = 4, c = 9
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cycles = (10 5 1 3 7 4 8 6 2)(9)

a = 5, b = 7, c = 10
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cycles = (10 4 6 9 2)(8)(7)(5 1 3)

a = 1, b = 3, c = 5
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cycles = (10 2 6 9 4)(8)(7)(5)(3)(1)

a = 2, b = 6, c = 10
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cycles = (10 5 8)(9)(7)(6)(4)(3)(2)(1)